(3/4x)^2+x^2=41/16x^2

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Solution for (3/4x)^2+x^2=41/16x^2 equation: 



(3/4x)^2+x^2=41/16x^2

We move all terms to the left:

(3/4x)^2+x^2-(41/16x^2)=0



Domain of the equation: 4x)^2!=0

x!=0/1

x!=0

x∈R





Domain of the equation: 16x^2)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

x^2+(+3/4x)^2-(41/16x^2)=0

We get rid of parentheses

x^2+(+3/4x)^2-41/16x^2=0

We calculate fractions


x^2+((+3*16x^2)/4x^2*16x^2)+(-164x)/4x^2*16x^2)=0



We calculate terms in parentheses: +((+3*16x^2)/4x^2*16x^2), so:

(+3*16x^2)/4x^2*16x^2

We multiply all the terms by the denominator


(+3*16x^2)

We get rid of parentheses

3*16x^2

Wy multiply elements

48x^2

Back to the equation:

+(48x^2)



We add all the numbers together, and all the variables

49x^2+(-164x)/4x^2*16x^2)=0

We get rid of parentheses

49x^2-164x)/4x^2*16x^2=0

We multiply all the terms by the denominator


49x^2*4x^2*16x^2-164x)=0

Wy multiply elements

3136x^6*1-164x)=0

We do not support expression: x^6

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